Sequelize error when using “where” and “in” on a subarray

Question

This is my model definition:

var Tag = sequelize.define(\'Tag\', {
    name: Sequelize.STRING
});

var Event = sequelize.define(\'Event\', {
    name: Sequelize.         


        

Answer 1

in property able to use at version 4.42

Tag.findAll({
    where: { id: {in: [1,2,3,4]} }
}).then(...)

And you can use notIn property for excluded values.

Tag.findAll({
    where: { id: {notIn: [1,2,3,4]} }
}).then(...)

http://docs.sequelizejs.com/manual/querying.html#operators