How can we truncate float64 type to a particular precision?

Question

package main

import (
    \"fmt\"
    \"strconv\"
    )

func main() {
    k := 10/3.0
    i := fmt.Sprintf(\"%.2f\", k)
    f,_ := strconv.ParseFloat(i, 2)
    fmt.Pri         


        

Answer 1

modify from @creack

package main

import (
    "fmt"
)

func main() {

    //untruncated := 10/3.0
    untruncated := 4.565
    tmp := int(untruncated*100)
    last := int(untruncated*1000)-tmp*10
    if last>=5{
        tmp += 1
    }
    truncated := float64(tmp)/100

    fmt.Println(untruncated, truncated)
}