Pass parameter to an awk script file

Question

If I want to pass a parameter to an awk script file, how can I do that ?

#!/usr/bin/awk -f

{print $1}

Here I want to print the first argument

Answer 1

You can use -v as a command-line option to provide a variable to the script:

Say we have a file script.awk like this:

BEGIN {print "I got the var:", my_var}

Then we run it like this:

$ awk -v my_var="hello this is me" -f script.awk
I got the var: hello this is me