java codility training Genomic-range-query

Question

The task is:

A non-empty zero-indexed string S is given. String S consists of N characters from the set of upper-case English letters A, C, G, T.

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Answer 1

Simple, elegant, domain specific, 100/100 solution in JS with comments!

function solution(S, P, Q) {
    var N = S.length, M = P.length;

    // dictionary to map nucleotide to impact factor
    var impact = {A : 1, C : 2, G : 3, T : 4};

    // nucleotide total count in DNA
    var currCounter = {A : 0, C : 0, G : 0, T : 0};

    // how many times nucleotide repeats at the moment we reach S[i]
    var counters = [];

    // result
    var minImpact = [];

    var i;

    // count nucleotides
    for(i = 0; i <= N; i++) {
        counters.push({A: currCounter.A, C: currCounter.C, G: currCounter.G});
        currCounter[S[i]]++;
    }

    // for every query
    for(i = 0; i < M; i++) {
        var from = P[i], to = Q[i] + 1;

        // compare count of A at the start of query with count at the end of equry
        // if counter was changed then query contains A
        if(counters[to].A - counters[from].A > 0) {
            minImpact.push(impact.A);
        }
        // same things for C and others nucleotides with higher impact factor
        else if(counters[to].C - counters[from].C > 0) {
            minImpact.push(impact.C);
        }
        else if(counters[to].G - counters[from].G > 0) {
            minImpact.push(impact.G);
        }
        else { // one of the counters MUST be changed, so its T
            minImpact.push(impact.T);
        }
    }

    return minImpact;
}