I have a pointer to function, assume any signature. And I have 5 different functions with same signature.
At run time one of them gets assigned to the pointer, and that
You will have to check which of your 5 functions your pointer points to:
if (func_ptr == my_function1) {
puts("func_ptr points to my_function1");
} else if (func_ptr == my_function2) {
puts("func_ptr points to my_function2");
} else if (func_ptr == my_function3) {
puts("func_ptr points to my_function3");
} ...
If this is a common pattern you need, then use a table of structs instead of a function pointer:
typedef void (*my_func)(int);
struct Function {
my_func func;
const char *func_name;
};
#define FUNC_ENTRY(function) {function, #function}
const Function func_table[] = {
FUNC_ENTRY(function1),
FUNC_ENTRY(function2),
FUNC_ENTRY(function3),
FUNC_ENTRY(function4),
FUNC_ENTRY(function5)
}
struct Function *func = &func_table[3]; //instead of func_ptr = function4;
printf("Calling function %s\n", func->func_name);
func ->func(44); //instead of func_ptr(44);