easy way to unzip file with golang

Question

is there a easy way to unzip file with golang ?

right now my code is:

func Unzip(src, dest string) error {
    r, err := zip.OpenReader(src)
    if err !         


        

Answer 1

I'm using archive/zip package to read .zip files and copy to the local disk. Below is the source code to unzip .zip files for my own needs.

import (
    "archive/zip"
    "io"
    "log"
    "os"
    "path/filepath"
    "strings"
)

func unzip(src, dest string) error {
    r, err := zip.OpenReader(src)
    if err != nil {
        return err
    }
    defer r.Close()

    for _, f := range r.File {
        rc, err := f.Open()
        if err != nil {
            return err
        }
        defer rc.Close()

        fpath := filepath.Join(dest, f.Name)
        if f.FileInfo().IsDir() {
            os.MkdirAll(fpath, f.Mode())
        } else {
            var fdir string
            if lastIndex := strings.LastIndex(fpath,string(os.PathSeparator)); lastIndex > -1 {
                fdir = fpath[:lastIndex]
            }

            err = os.MkdirAll(fdir, f.Mode())
            if err != nil {
                log.Fatal(err)
                return err
            }
            f, err := os.OpenFile(
                fpath, os.O_WRONLY|os.O_CREATE|os.O_TRUNC, f.Mode())
            if err != nil {
                return err
            }
            defer f.Close()

            _, err = io.Copy(f, rc)
            if err != nil {
                return err
            }
        }
    }
    return nil
}