C++ template specialization without default function

Question

I have the following code that compiles and works well:

template
T GetGlobal(const char *name);

template<>
int GetGlobal(cons         


        

Answer 1

To get a compile-time error implement it as:

template
T GetGlobal(const char *name) { T::unimplemented_function; }
// `unimplemented_function` identifier should be undefined

If you use Boost you could make it more elegant:

template
T GetGlobal(const char *name) { BOOST_STATIC_ASSERT(sizeof(T) == 0); }

C++ Standard guarantees that there is no such type which has sizeof equal to 0, so you'll get a compile-time error.

As sbi suggested in his comments the last could be reduced to:

template
T GetGlobal(const char *name) { char X[!sizeof(T)]; }

I prefer the first solution, because it gives more clear error message (at least in Visual C++) than the others.