Difference between uint and unsigned int?

Question

Is there any difference between uint and unsigned int? I\'m looking in the site, but all question refers to C# or C++. I\'d like to have an answer conc

Answer 1

All of the answers here fail to mention the real reason for uint.
It's obviously a typedef of unsigned int, but that doesn't explain its usefulness.

The real question is,

Why would someone want to typedef a fundamental type to an abbreviated version?

To save on typing?
No, they did it out of necessity.

Consider the C language; a language that does not have templates.
How would you go about stamping out your own vector that can hold any type?

You could do something with void pointers,
but a closer emulation of templates would have you resorting to macros.

So you would define your template vector:

#define define_vector(type) \
  typedef struct vector_##type { \
    impl \
  };

Declare your types:

define_vector(int)
define_vector(float)
define_vector(unsigned int)

And upon generation, realize that the types ought to be a single token:

typedef struct vector_int { impl };
typedef struct vector_float { impl };
typedef struct vector_unsigned int { impl };