Assume we have two numeric vectors x and y. The Pearson correlation coefficient between x and y is given by
Here's another possibility with the outliers captured. Using a similar scheme as Prasad:
library(mvoutlier)
set.seed(1)
x <- rnorm(1000)
y <- rnorm(1000)
xy <- cbind(x, y)
outliers <- aq.plot(xy, alpha=0.975) #The documentation/default says alpha=0.025. I think the functions wants 0.975
cor.plot(x, y)
color.plot(xy)
dd.plot(xy)
uni.plot(xy)
In the other answers, 500 was stuck on the end of x and y as an outlier. That may, or may not cause a memory problem with your machine, so I dropped it down to 4 to avoid that.
x1 <- c(x, 4)
y1 <- c(y, 4)
xy1 <- cbind(x1, y1)
outliers1 <- aq.plot(xy1, alpha=0.975) #The documentation/default says alpha=0.025. I think the functions wants 0.975
cor.plot(x1, y1)
color.plot(xy1)
dd.plot(xy1)
uni.plot(xy1)
Here are the images from the x1, y1, xy1 data:


