Row-major vs Column-major confusion

Question

I\'ve been reading a lot about this, the more I read the more confused I get.

My understanding: In row-major rows are stored contiguously in memory, in column-major colu

Answer 1

Given the explanations above, here is a code snippet demonstrating the concept.

//----------------------------------------------------------------------------------------
// A generalized example of row-major, index/coordinate conversion for
// one-/two-dimensional arrays.
// ex: data[i] <-> data[r][c]
//
// Sandboxed at: http://swift.sandbox.bluemix.net/#/repl/5a077c462e4189674bea0810
//
// -eholley
//----------------------------------------------------------------------------------------

// Algorithm

let numberOfRows    = 3
let numberOfColumns = 5
let numberOfIndexes = numberOfRows * numberOfColumns

func index(row: Int, column: Int) -> Int {
    return (row * numberOfColumns) + column
}

func rowColumn(index: Int) -> (row: Int, column: Int) {
    return (index / numberOfColumns, index % numberOfColumns)
}

//----------------------------------------------------------------------------------------

// Testing

let oneDim = [
       0,    1,    2,    3,    4,
       5,    6,    7,    8,    9,
      10,   11,   12,   13,   14,
]

let twoDim = [
    [  0,    1,    2,    3,    4 ],
    [  5,    6,    7,    8,    9 ],
    [ 10,   11,   12,   13,   14 ],
]

for i1 in 0..