Comparing times only, without dates?

Question

I need to write a method that will check if Time.now is in between the open hours and the close hours of a shop.

The open and close hours are saved as a Tim

Answer 1

Try converting the Time into a number and strip off the days. Since the Time is represented as a number of seconds since the UNIX Epoch with the decimal being a fraction of the second, you can convert this number to a number of days with the fraction being a fraction of a day.

Day based number = Ruby Time Number / 60 / 60 / 24

You can then use the modulus operator to strip the day portion so all you have left to compare is the time. So you want something like this:

def is_open?(time)
  open_h=Time.parse('2012-02-02 02:30:00 UTC')
  close_h=Time.parse('2012-02-02 10:00:00 UTC')
  (((time.to_r / 60 / 60 / 24) % 1) >= ((open_h.to_r / 60 / 60 / 24) % 1)) && (((time.to_r / 60 / 60 / 24) % 1) <= ((close_h.to_r / 60 / 60 / 24) % 1))
end

is_open? (Time.parse('2013-01-01 09:58:00 UTC'))
=> true
is_open? (Time.parse('2013-01-01 12:58:00 UTC'))
=> false