How to print an exception in Python 3?

Question

Right now, I catch the exception in the except Exception: clause, and do print(exception). The result provides no information since it always prints

Answer 1

[In Python3]

Let's say you want to handle an IndexError and print the traceback, you can do the following:

from traceback import print_tb 
empty_list = [] 
try: 
    x = empty_list[100]
except IndexError as index_error: 
    print_tb(index_error.__traceback__)

Note: You can use the format_tb function instead of print_tb to get the traceback as a string for logging purposes. Hope this helps.