Given a vector of strings, I would like to create an expression without the quotation marks.
# eg, I would like to go from
c(\"string1\", \"string2\")
# to...
I found these answers helpful but incomplete for using variables and multiple lines within the expression. To create a quoted expression from strings, with variables and multiple lines make use of quote(), atop() and subsititute():
# Prepare variables
samp_skewness = round(skewness(dv),2)
samp_kurtosis = round(kurtosis(dv),2)
samp_var = round(var(dv))
samp_summ <- summary(dv)
num_samples = length(dv)
# Prepare quotes containing math annotations
q1 = quote(paste(mu,"="))
q2 = quote(paste(sigma,"="))
q3 = quote(paste(gamma[1],"="))
q4 = quote(paste(gamma[2],"="))
# Use subsitition to construct the expression, passing in the variables and quoted expressions
title = substitute(atop(paste("Top Title, # samples: ", ns),
paste(e1,v1,", ",e2,v2,", ",e3,v3,", ",e4,v4)),
list(ns=num_samples,v1=round(samp_summ['Mean']),v2=samp_var,
v3=samp_skewness,v4=samp_kurtosis,e1=q1,e2=q2,e3=q3,e4=q4))
In ggplot: ...
labs(title = title) +
...