Java Generics Hell

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忘掉有多难
忘掉有多难 2021-01-31 09:18

I suspect this has been asked here (and answered) before, but I don\'t know how to name the problem. Why can I express the wildcards without problem only when I\'m not passing

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  •  天命终不由人
    2021-01-31 10:09

    The type of ShapeSaver.class is Class. When feed it to genericsHell(), compiler needs to check if Class is a subtype of Class, which is reduces to whether ShapeSaver is a subtype of ShapeProcessor. The subtype relation does not hold, the method call fails.

    The same thing should be true for @Bohemian's solution. Here the subtype checking occurs at bound checking of T after T is inferred. It should fail too. This appears to be a compiler bug, which somehow misinterprets the rule that Raw is assignable to Raw as if Raw is a subtype of Raw. see also Enum.valueOf throws a warning for unknown type of class that extends Enum?

    A simple solution to your problem is to declare

    void genericsHell(Class a)
    

    indeed, ShapeSaver is a subtype of ShapeProcessor, and the call compiles.

    That's not just a workaround. There's a good reason for it. Strictly speaking, for any Class, X must be a raw type. For example, Class is ok, Class> is not. Because there is really no class that represents List; there is only a class representing List.

    Ignore the stern warning that you shall not use raw type. We must use raw types sometimes, given how Java type system is designed. Even Java's core APIs (Object.getClass()) use raw types.


    You probably intended to do something like this

    genericsHell(ShapeSaver.class);
    

    Unfortunately, that's not allowed. Java could have, but did not, introduce type literal along with generics. That created lots of problems for lots of libraries. java.lang.reflect.Type is a mess and unusable. Every library has to introduce their own representation of type system to solve the problem.

    You can borrow one, e.g. from Guice, and you'll be able to

    genericsHell( new TypeLiteral< ShapeSaver >(){} )
                                   ------------------  
    

    (learn to skip the craps around ShaveSaver when reading the code)

    In the method body of genericsHell(), you'll have full type information, not just the class.

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