C++ template argument type deduction

Question

Given a templated function declared like this:

template
int Function(T object);

A user can invoke this function by specifying th

Answer 1

In C++17, you can have auto non-type template parameters. This will let you solve your problem.

Something like:

template>
int Function();

(assuming you want the type T within the body of Function)

In C++14, the C++17 feature is missing. It was added exactly because it was missing. Workarounds involve macros like #define UGLY_HACK(...) decltype(__VA_ARGS__), __VA_ARGS__.