How to build a conditional assignment in bash?

Question

I\'m looking a way to build conditional assignments in bash:

In Java it looks like this:

int variable= (condition) ? 1 : 0;

Answer 1

In addition to the other more general answers (particularly as per Jonathan's comment and Kevin's more general answer [which also supports strings]) I'd like to add the following two solutions:

setting the variable to either 0 or 1 based on the condition:

(as the question's example suggests.)

The general form would read

(condition); variable=$?;

where $variable results in being either 0 or 1 and condition can be any valid conditional expression.

E.g. checking a variable ...

[[ $variableToCheck == "$othervariable, string or number to match" ]]
variable=$?

... or checking a file's existence ...

[ -f "$filepath" ]
fileExists=$?

... or checking the nummerical value of $myNumber:

(( myNumber >= 1000000000 ))
is_huge_number=$?

The advantages of this solution is that

• it supports arbitrary conditional expressions, including strings
  (which are not supported in arithmetic expressions of Jonathan's solution)
• that variable gets declared in any case, unlike in griffon's answer:
  [ -z "$variable" ] && variable="defaultValue"
  Which would matter in case you want to nameref it later on (e.g. from within a function).

Please note: In Bash, the special variable $? always contains the exit code of the previously executed statement (or statement block; see the man bash for more details). As such, a positive result is generally represented by the value 0, not 1 (See my comment below, thanks Assimilater for pointing it out). Thus, if the condition is true (e.g [[2 eq 2]]) then $?=0.

If instead you need 0 or 1 in your variable (e.g. to print or do mathematical calculations) then you need to employ boolean negation using a leading exclamation mark (as pointed out by GypsySpellweaver in the comments below): ( ! condition ); variable=$? or ! ( condition ); variable=$?. (However, readability in terms of what happens might be a bit less obvious.)

Another possible solution by Jonathan would be variable=$(( 1 == 1 ? 1 : 0 )) - which, however, is creating a subshell.

If you want to avoid the creation of a subshel, keep good readability or have arbitrary conditions, use one of the following solutions.

setting the variable to arbitrary values:

as it is done in most other answers, it could adapted as follows:

(condition) \
    && variable=true \
    || variable=false

e.g as in

[[ $variableToCheck == "$othervariable, string or number to match" ]] \
    && variable="$valueIfTrue" \
    || variable="$valueIfFalse"

or to get 1 in a positive check, and 0 upon failure (like in the question's example):

[[ $variableToCheck == "$othervariable, string or number to match" ]] \
    && variable=1 \
    || variable=0

(for the last example, - as already mentioned in the notes above - the same can be achieved with boolean negation using a leading exclamation mark:

[[ ! $variableToCheck == "$othervariable, string or number to match" ]]
variable=$?

The advantages of this solution is that

• it might be considered a bit better readable than Kevin's answer
  myvar="default" && [[ ]] && myvar="non-default", and
• the $valueIfTrue is conditionally evaluated only if needed,
  which would matter in case you'd do something
  • with side-effect, like
    • variable=$((i++)), or
    • { variable=$1; shift; }
  • high computation, like
    • variable=$(find / -type f -name ListOfFilesWithThisNameOnMySystem)
• is a bit shorter than ghostdog74's answer
  (which, however is great if you have multiple conditions!)
• does not open a subshell as in Pierre's answer
• and as above:
  • it supports arbitrary conditional expressions, including strings
    (which are not supported in arithmetic expressions of Jonathan's solution)
  • that variable gets declared in any case, unlike in griffon's answer:
    [ -z "$variable" ] && variable="defaultValue"
    Which would matter in case you want to nameref it later on (e.g. from within a function).