Socket.io Connected User Count

Question

I finally got socket.io to work properly, but I have encountered a strange problem.

I am not sure if this is the best way, but I am using:

io.sockets.cli         


        

Answer 1

I don't see any mention of multi core apps so I'm just gonna add that since I am using multiple cores ( clusters ) I wasn't able to get the right number of sockets consistently on the client side, so I ended up saving them to my mongo instance and it is quite consistent and accurate. With this approach I can view my socket connections in style via the browser :).

Mongoose schema :

var socketSchema = mongoose.Schema({
        socket : Number
});

Usage:

//reset to 0 when the app starts ( just in case )
SocketModel.find({ "socket" : 1 } , function(err, deadSockets ) {
    if (err){
        console.log( err );
    }
    else{
        for( var i = 0 ; i < deadSockets.length ; i++ ){
            deadSockets[i].remove();                
        }
    }
});

io.on('connection', function( socket ) {
    //I found I needed to make sure I had a socket object to get proper counts consistantly
    if( socket ){
        var socketEntry = new SocketModel({ "socket" : 1 });
        socketEntry.save( function(err ){
            if (err){
                console.log( err );
            }
            else{
        
            }
        });
    }
    //On Disconnect
    socket.on('disconnect', function() {
        SocketModel.findOne({ "socket" : 1} , function(err, deadSocket ) {
            if (err){
                console.log( err );
            }
            else{
                deadSocket.remove();
            }
        }); 
    });
});

How many do I have ?

SocketModel.count({ "socket" : 1 } , function(err, count ) {
    if (err){
        console.log(err);
    }
    else{
        var term = "sockets";
        if( count == 1 ) term = "socket";
        console.log("Current Load: " , count , term );
    }
}); 

NOTE I don't like using empty query objects ( {} ) so I just used { "socket" : 1 } as a dummy instead