How do you call a function defined in .bashrc from the shell?

Question

In my .bashrc, I have a function called hello:

function hello() {
   echo \"Hello, $1!\"
}

I want to be able to invoke hello() from the shell a

Answer 1

The test in your function won't work - you should not have brackets around the -z clauses, and there should be a space between if and the open bracket. It should read:

function coolness() {

    if [ -z "$1" -o -z "$2" ]; then
        echo "Usage: $0 [sub_package] [endpoint]";
        exit 1;
    fi
    echo "Hi!"
}