Lazy evaluation in Ruby

Question

I have a situation for Ruby, where an object is possibly necessary to be created, but it is not sure. And as the creation of the object might be costly I am not too eager creati

Answer 1

There are two ways.

The first is to let the caller handle lazy object creation. This is the simplest solution, and it is a very common pattern in Ruby code.

class ExpensiveObject
  def initialize
    # Expensive stuff here.
  end
end

class Caller
  def some_method
    my_object.do_something
  end

  def my_object
    # Expensive object is created when my_object is called. Subsequent calls
    # will return the same object.
    @my_object ||= ExpensiveObject.new
  end
end

The second option is to let the object initialise itself lazily. We create a delegate object around our actual object to achieve this. This approach is a little more tricky and not recommended unless you have existing calling code that you can't modify, for example.

class ExpensiveObject        # Delegate
  class RealExpensiveObject  # Actual object
    def initialize
      # Expensive stuff here.
    end

    # More methods...
  end

  def initialize(*args)
    @init_args = args
  end

  def method_missing(method, *args)
    # Delegate to expensive object. __object method will create the expensive
    # object if necessary.
    __object__.send(method, *args)
  end

  def __object__
    @object ||= RealExpensiveObject.new(*@init_args)
  end
end

# This will only create the wrapper object (cheap).
obj = ExpensiveObject.new

# Only when the first message is sent will the internal object be initialised.
obj.do_something

You could also use the stdlib delegate to build this on top of.