Is there a way to programmatically check if a user shared a link on Facebook?

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面向向阳花
面向向阳花 2021-01-30 11:39

I\'m currently using jQuery to record each click on a Facebook share link on my site, but I\'m looking for a more accurate solution. Instead of recording the clicks, I\'d like t

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  •  没有蜡笔的小新
    2021-01-30 12:34

    For as long as it remains active, you can use the Facebook "Feed" dialog rather than the "Share" dialog to ALWAYS get a share confirmation. (This applies to the Javascript Facebook SDK.)

    Here's my understanding of the differences between the two:


    Share Method

    FB.ui({
        method: 'share',
        href: 'http://stackoverflow.com/questions/5363517',
    }, function(response){
       console.log(response)
    });
    

    If the user is LOGGED IN and authorized your app:

    • If the post was shared, you will get a post id in the response variable: {post_id: "10205041067000110_10205045578512895"}.
    • If the post was not shared, response will be null.

    If the user is NOT LOGGED IN to your app (they still need to be logged into Facebook):

    • The response variable will be null regardless of whether the user shared or did not share.

    Thus, if you absolutely need the share confirmation, you have to ask the user to login first. This may not be a problem for your app, but in my case this added unnecessary friction to the sharing process.


    Feed Method

    (Deprecated but still active)

    FB.ui({
      method: 'feed',
      link: 'http://stackoverflow.com/questions/5363517',
      caption: 'Test Caption',
    }, function(response){
        console.log(response)
    });
    

    IRRESPECTIVE of login status (w.r.t. your app; they still need to be logged into Facebook):

    • If a post was actually shared, the response variable returned by Facebook will have the post id: {post_id: "10205041067000110_10205045578512895"}.
    • If the post was not shared, response will be null.

    Using this method, you will always be able to tell whether someone posted or not, regardless of their login status.

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