What should I use to open a url instead of urlopen in urllib3

Question

I wanted to write a piece of code like the following:

from bs4 import BeautifulSoup
import urllib2

url = \'http://www.thefamouspeople.com/singers.php\'
html = u         


        

Answer 1

With gazpacho you could pipeline the page straight into a parse-able soup object:

from gazpacho import Soup
url = "http://www.thefamouspeople.com/singers.php"
soup = Soup.get(url)

And run finds on top of it:

soup.find("div")