phpunit avoid constructor arguments for mock

Question

What is the way to avoid phpunit having to call the constructor for a mock object? Otherwise I would need a mock object as constructor argument, another one for that etc. The ap

Answer 1

As an addendum, I wanted to attach expects() calls to my mocked object and then call the constructor. In PHPUnit 3.7.14, the object that is returned when you call disableOriginalConstructor() is literally an object.

// Use a trick to create a new object of a class
// without invoking its constructor.
$object = unserialize(
sprintf('O:%d:"%s":0:{}', strlen($className), $className)

Unfortunately, in PHP 5.4 there is a new option which they aren't using:

ReflectionClass::newInstanceWithoutConstructor

Since this wasn't available, I had to manually reflect the class and then invoke the constructor.

$mock = $this->getMockBuilder('class_name')
    ->disableOriginalConstructor()
    ->getMock();

$mock->expect($this->once())
    ->method('functionCallFromConstructor')
    ->with($this->equalTo('someValue'));

$reflectedClass = new ReflectionClass('class_name');
$constructor = $reflectedClass->getConstructor();
$constructor->invoke($mock);

Note, if functionCallFromConstruct is protected, you specifically have to use setMethods() so that the protected method is mocked. Example:

    $mock->setMethods(array('functionCallFromConstructor'));

setMethods() must be called before the expect() call. Personally, I chain this after disableOriginalConstructor() but before getMock().