Does unique_ptr::release() call the destructor?

Question

Is this code correct?

auto v =  make_unique(12);
v.release();     // is this possible?

Is it equivalent to delete of a

Answer 1

Is this code correct?

No. Use std::unique_ptr<>::reset() to delete the internal raw pointer:

auto v =  std::make_unique(12);
v.reset(); // deletes the raw pointer

After that is done, std::unique_ptr<>::get() will return nullptr (unless you provided a non-nullptr parameter to std::unique_ptr<>::reset()).