Why does this Java code compile?

Question

In method or class scope, the line below compiles (with warning):

int x = x = 1;

In class scope, where variables get their default valu

Answer 1

In java or in any modern language, assignment comes from the right.

Suppose if you are having two variables x and y,

int z = x = y = 5;

This statement is valid and this is how the compiler splits them.

y = 5;
x = y;
z = x; // which will be 5

But in your case

int x = x + 1;

The compiler gave an exception because, it splits like this.

x = 1; // oops, it isn't declared because assignment comes from the right.