How to include file in a bash shell script

Question

Is there a way to include another shell script in a shell script to be able to access its functions?

Like how in PHP you can use the include directive with

Answer 1

Simply put inside your script :

source FILE

Or

. FILE # POSIX compliant

$ LANG=C help source
source: source filename [arguments]
Execute commands from a file in the current shell.

Read and execute commands from FILENAME in the current shell.  The
entries in $PATH are used to find the directory containing FILENAME.
If any ARGUMENTS are supplied, they become the positional parameters
when FILENAME is executed.

Exit Status:
Returns the status of the last command executed in FILENAME; fails if
FILENAME cannot be read.