How to get a list of all Subversion commit author usernames?

Question

I\'m looking for an efficient way to get the list of unique commit authors for an SVN repository as a whole, or for a given resource path. I haven\'t been able to find an SVN co

Answer 1

To filter out duplicates, take your output and pipe through: sort | uniq. Thus:

svn log --quiet | grep "^r" | awk '{print $3}' | sort | uniq

I woud not be surprised if this is the way to do what you ask. Unix tools often expect the user to do fancy processing and analysis with other tools.

P.S. Come to think of it, you can merge the grep and awk...

svn log --quiet | awk '/^r/ {print $3}' | sort | uniq

P.P.S. Per Kevin Reid...

svn log --quiet | awk '/^r/ {print $3}' | sort -u

P³.S. Per kan, using the vertical bars instead of spaces as field separators, to properly handle names with spaces (also updated the Python examples)...

svn log --quiet | awk -F ' \\\\|' '/^r/ {print $2}' | sort -u

For more efficient, you could do a Perl one-liner. I don't know Perl that well, so I'd wind up doing it in Python:

#!/usr/bin/env python
import sys
authors = set()
for line in sys.stdin:
    if line[0] == 'r':
        authors.add(line.split('|')[1].strip())
for author in sorted(authors):
    print(author)

Or, if you wanted counts:

#!/usr/bin/env python
from __future__ import print_function # Python 2.6/2.7
import sys
authors = {}
for line in sys.stdin:
    if line[0] != 'r':
        continue
    author = line.split('|')[1].strip()
    authors.setdefault(author, 0)
    authors[author] += 1
for author in sorted(authors):
    print(author, authors[author])

Then you'd run:

svn log --quiet | ./authorfilter.py