Detecting patterns in waves

Question

I\'m trying to read a image from a electrocardiography and detect each one of the main waves in it (P wave, QRS complex and T wave). Now I can read the image and get a vector li

Answer 1

First, the various components of the standard electrocardiogram wave can be missing from any given plot. Such a plot is generally abnormal and usually indicates some sort of problem, but you can't be promised that they're there.

Secondly, recognizing them is as much art as science, especially in the cases where something is going wrong.

My approach might be to try to train a neural network to identify the components. You would give it the previous 30 seconds of data, normalized so the lowest point was at 0 and the highest point at 1.0 and it would have 11 outputs. The outputs that weren't abnormality ratings would be a weighting for the last 10 seconds. A 0.0 would be -10 seconds from present, and a 1.0 would mean now. The outputs would be:

1. Where the most recent P wave started
2. Where the most recent P wave ended
3. Abnormality rating of most recent P wave with one extreme being 'absent'.
4. Where the most recent QRS complex started
5. Where the Q portion of the most recent QRS complex turned into the R portion.
6. Where the R portion of the most recent QRS complex turned into the S portion.
7. Where the most recent QRS complex ended.
8. Abnormality rating of most recent QRS complex with one extreme being 'absent'.
9. Where the most recent T wave started.
10. Where the most recent T wave ended.
11. Abnormality rating of most recent T wave with one extreme being 'absent'.

I might double check this with some of the other kinds of analysis people suggested, or use those other kinds of analysis along with the output of the neural network to give you your answer.

Of course, this detailed description of the neural network shouldn't be taken as prescriptive. I'm sure that I didn't necessarily pick the most optimal outputs for example, I just sort of tossed some ideas about what they might be.