Precendence vs short-circuiting in C [closed]

Answer 1

The ++s don't execute before the expression. Only ++i executes, which indicates that the result of the expression will be 1, therefore the rest of the expression is not evaluated (short circuit).

Your code is equivalent to:

if (++i)
    m = 1;
else
    if (!++j)
        m = 0;
    else if (!++i)
        m = 0;
    else
        m = 1;

This means that once ++i is evaluated to true, the else part is never executed.