Convert char array to hex array (C++)

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[愿得一人] 2021-01-29 16:17

My problem is converting array of chars to array of hexadecimal numbers, i need to take 2chars from char array and conver them into one hex number.

This is my input:

2条回答

自闭症患者 (楼主)

2021-01-29 17:11

en,my english is bad,so i write the code hope to explain what i think. personally speacking i think we can write a function for this question.

#include 
#include 
#include 
#include 
#include 

using namespace std;

map convertTable;
void initHexTable();
void convertToHex(unsigned char * text, unsigned char * hexval, int &i);
void print(unsigned char *p, int len);

char hexIndex[] = {'0','1','2','3','4','5','6','7','8','9','a', 'b', 'c', 'd', 'e', 'f'};
int main() {

    unsigned char text[1024]= "06fb7405eba8d9e94fb1f28f0dd21fdec55fd54750ee84d95ecccf2b1b48";
    unsigned char hexval[1024];
    int len = 0;
    initHexTable();
    convertToHex(text, hexval, len);
    print(hexval, len);
    return 0;
}

void initHexTable() {

    for (int i = 0; i < 16; i++) {

        for (int j = 0; j < 16; j++) {
             string key;
             key += hexIndex[i]; key += hexIndex[j];
             //cout << key << " ";
             convertTable[key] = i * 16 + j;

        }

    }
}

void convertToHex(unsigned char * text, unsigned char * hexval, int &i) {

    string s((char *)text);
    string key;
    int str_size = strlen((char*)text);
    //cout << "str_size = " << str_size;
    int start = 0, len = 2;
    for (;;) {
        if (start >= str_size) break;
        key = s.substr(start, len);
        //cout << " "<