How to transform a list into a CSV file with N items per row?

Question

I want to create a new CSV file with 3 items per row. My source file looks like (there are no new lines / line breaks):

Answer 1

I wrote a short program that I think does what you wanted:

It reads all lines from the reader file and then just insert them into the writer file 3 by 3 :)

import csv

def main():

    with open('ex.csv', 'rb') as f:
    reader = csv.reader(f)
    with open('ex2.csv', 'wb') as csvfile:
        writer = csv.writer(csvfile)
        pass_on = []

        for row in reader:
            #print row

            for c in xrange(0, len(row)): # passing on objects after count of 3
                if row[c]:
                    pass_on.append(row[c])


        print pass_on

        while pass_on:

            writer.writerow(pass_on[:3])
            pass_on = pass_on[3:]



    print "done"

if __name__ == '__main__':
    main()