sizeof on argument

Question

Even with int foo(char str[]); which will take in an array initialized to a string literal sizeof doesn\'t work. I was asked to do something like strlen and the app

Answer 1

C strings are just arrays of char. Arrays are not passed by value in C; instead, a pointer to their first element is passed.

So these two are the same:

void foo(char blah[]) { ... }
void foo(char *blah)  { ... }

and these two are the same:

char str[] = "Hello";
foo(str);

char *p = str;
foo(p);