Initialize 2D array dynamically only knowing its column size in C [closed]

Answer 1

Maybe a typedef will help you?

#include 
#include 

void seqr(void *d, int n) {
    int *a = d;
    for (int k = 0; k < n; k++) a[k] = k;
}

typedef int row10[10]; // helper typedef

int main(void) {
    int n = 42;
    row10 *rows = malloc(n * sizeof *rows);
    if (rows) {
        seqr(rows, n * 10);
        printf("%d, %d\n", rows[0][0], rows[n - 1][9]);
        free(rows);
    }
    return 0;
}