Delete record where duplicate in part of raw

Question

I need to delete all records in a table where the time between it 1 or 2 minute or the same and must be the same ID but keep the first record

ID            


        

Answer 1

Here you go!

DECLARE @Seconds INT = 120
DECLARE @Logs TABLE (
    ID INT,
    [Time] DATETIME
)
INSERT @Logs VALUES
(10, '2014-06-30 19:17:37.000'),
(10, '2014-06-30 19:17:42.000'),
(10, '2014-06-30 19:17:46.000'),
(10, '2014-06-30 19:17:58.000'),
(10, '2014-06-30 20:37:46.000'),
(10, '2014-07-01 21:10:33.000'),
(10, '2014-07-01 21:11:06.000'),
(10, '2014-07-02 20:53:36.000'),
(10, '2014-07-02 20:53:38.000'),
(10, '2014-07-02 20:54:33.000'),
(10, '2014-07-02 20:54:41.000'),
(10, '2014-07-02 20:55:22.000')

;WITH Logs AS (
    SELECT
        ID,
        [Time],
        ROW_NUMBER() OVER (PARTITION BY ID ORDER BY [Time]) AS RowNum
    FROM @Logs L
)
    --SELECT *, DATEDIFF(SS, L1.[Time], L2.[Time])
    DELETE L2
    FROM Logs L1
        INNER JOIN Logs L2
            ON L1.ID = L2.ID
                AND L1.RowNum = L2.RowNum - 1
    WHERE DATEDIFF(SS, L1.[Time], L2.[Time]) < @Seconds
SELECT * FROM @Logs