C output question

Question

Why its output is %%??

#include
int main(void)
{
        printf(\"% % %\\n\");
return 0;
}

Answer 1

If you use one %, it sees it as string (because it lacks other specifiers) and output %. If you use %%, it is to print % in output. if you use %%% the first two will be considered as outputting % and the last one as single "character". so you only get two %.