Write a Regex to extract number before '/'

Question

I don\'t want to use string split because I have numbers 1-99, and a column of string that contain \'#/#\' somewhere in the text.

How can I write a regex to extract the

Answer 1

You can still use str.split() if you carefully construct logic around it:

t = "He got 10/19 questions right."
t2 = "He/she got 10/19 questions right"


for q in [t,t2]:


    # split whole string at spaces
    # split each part at / 
    # only keep parts that contain / but not at 1st position and only consists
    # out of numbers elsewise
    numbers = [x.split("/") for x in q.split() 
               if "/" in x and all(c in "0123456789/" for c in x)
              and not x.startswith("/")]
    if numbers:
        print(numbers[0][0])

Output:

10
10