Change a dynamic's type in a ternary conditional statement

Question

In C#, the type dynamic allows you to change a variable\'s type at runtime, for example:

dynamic x = \"foo\";
x = 42;

Another exam

Answer 1

The specification has this to say about how it uses the operands to determine the type of a ternary expression:

The second and third operands, x and y, of the ?: operator control the type of the conditional expression.

•If x has type X and y has type Y then,

o If X and Y are the same type, then this is the type of the conditional expression.

o Otherwise, if an implicit conversion (§11.2) exists from X to Y, but not from Y to X, then Y is the type of the conditional expression.

o Otherwise, if an implicit enumeration conversion (§11.2.4) exists from X to Y, then Y is the type of the conditional expression.

o Otherwise, if an implicit enumeration conversion (§11.2.4) exists from Y to X, then X is the type of the conditional expression.

o Otherwise, if an implicit conversion (§11.2) exists from Y to X, but not from X to Y, then X is the type of the conditional expression.

o Otherwise, no expression type can be determined, and a compile-time error occurs.

Obviously none of these (excluding the final statement) are true for string and int, so you get the compile time error.

Essentially, the type of the variable you're assigning the result of your ternary to doesn't have an impact on the resulting type of the ternary expression. If you want to return dynamic, you'll need to cast one of the operands to dynamic directly, like so:

dynamic x = (true) ? (dynamic) "foo" : 42;