Is this always the address for GDB debug program?

Question

I will narrow down my questions:

The entry address in GDB stays the same for the same program (even after reboot, and after rewriting the source code).

Why is th

Answer 1

For example 0x80483f4 is the starting address.

This is likely. Unless you have PIE (position independent executables), it will stay the same (for one binary) forever.

$2 = 0x80483fa 
(gdb) x $2
0x80483fa :   0x3fc45c7

That is the binary representation of the instructions at main()+6. Will never change in one binary.

(gdb) p 0x3fc45c7
$3 = 66864583   <-- even after reboot.

That means 0x3fc45c7 is 66864583 in decimal...

Note that none of this has anything to do with a or b.

BTW the best way to get values of variables "before assignment" is to printf them before the assignment.