How to produce executable with rustc?

Question

If I compile this simple program fn main() { println!(\"Hello\"); } with rustc test.rs -o test then I can run it with ./test, but double c

Answer 1

What you have described is not entirely consistent with what I observe:

$ rustc - -o test <<< 'fn main() { println!("Hello"); }' 
$ ./test
Hello
$ file test
test: ELF 64-bit LSB shared object, x86-64, version 1 (SYSV), dynamically linked (uses shared libs), for GNU/Linux 2.6.32, BuildID[sha1]=99e97fcdc41eb2d36c950b8b6794816b05cf854c, not stripped

Unless you tell rustc to produce a library with e.g. #![crate_type = "lib"] or --crate-type lib, it will produce an executable.

It sounds like your file manager may be being too smart for its own good. It should just be trusting the executable bit and executing it.