The system cannot find the path specified (Batch file) - Using path with white spaces - PENTAHO spoon.bat (pdi-ce-7.1.0.0-12)

Question

I\'m trying to execute a batch file \"spoon.bat\" from PENTAHO (pdi-ce-7.1.0.0-12), but there is an error.

Part of batch file where the error is found:

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Answer 1

Where is the environment variable PENTAHO_JAVA referenced?

It must be referenced with "%PENTAHO_JAVA%" because the string assigned to this environment variable contains characters like a space or &()[]{}^=;!'+,`~. This is explained in help of Windows command interpreter output on running in a command prompt window cmd /? in last paragraph on last help page.

It is of course also possible to define the environment variable with the necessary double quotes already added, i.e. use:

if     "%SPOON_CONSOLE%"=="1" set "PENTAHO_JAVA="%ProgramFiles(x86)%\Java\jre1.8.0_121\bin\java.exe""
if not "%SPOON_CONSOLE%"=="1" set "PENTAHO_JAVA="%ProgramFiles(x86)%\Java\jre1.8.0_121\bin\javaw.exe""
set "IS64BITJAVA=0"
call "%~dp0set-pentaho-env.bat"

But this is not recommended. Better would be to use

if     "%SPOON_CONSOLE%"=="1" set "PENTAHO_JAVA=%ProgramFiles(x86)%\Java\jre1.8.0_121\bin\java.exe"
if not "%SPOON_CONSOLE%"=="1" set "PENTAHO_JAVA=%ProgramFiles(x86)%\Java\jre1.8.0_121\bin\javaw.exe"
set "IS64BITJAVA=0"
call "%~dp0set-pentaho-env.bat"

and reference environment variable PENTAHO_JAVA enclosed in double quotes where it is necessary to specify its value enclosed in double quotes.

Example:

@echo off
rem Get path of latest installed Java directly from Windows registry.
for /F "skip=1 tokens=1,2*" %%N in ('%SystemRoot%\System32\reg.exe QUERY "HKLM\Software\Microsoft\Windows\CurrentVersion\App Paths\javaws.exe" /v Path 2^>nul') do if /I "%%N" == "Path" set "PENTAHO_JAVA=%%P" & goto JavaPathFound

rem Path of Java not found in registry, search for 32-bit Java in the default
rem program files folders of 64-bit and 32-bit Windows and take first found.
if "%ProgramFiles(x86)%" == "" goto Windows_x86
for /R "%ProgramFiles(x86)%" %%I in (java*.exe) do set "PENTAHO_JAVA=%%~dpI" & goto JavaPathFound
:Windows_x86
for /R "%ProgramFiles%" %%I in (java*.exe) do set "PENTAHO_JAVA=%%~dpI" & goto JavaPathFound

echo Error: Java binary directory not found.
echo/
pause
goto :EOF

:ErrorJavaEXE
echo Error: File %PENTAHO_JAVA% not found.
echo/
pause
goto :EOF

:JavaPathFound
if not "%PENTAHO_JAVA:~-1%" == "\" set "PENTAHO_JAVA=%PENTAHO_JAVA%\"
if "%SPOON_CONSOLE%" == "1" (
    set "PENTAHO_JAVA=%PENTAHO_JAVA%java.exe"
) else (
    set "PENTAHO_JAVA=%PENTAHO_JAVA%javaw.exe"
)

rem Check existence of Java executable to run.
if not exist "%PENTAHO_JAVA%" goto ErrorJavaEXE

"%PENTAHO_JAVA%" -version
call "%~dp0set-pentaho-env.bat"

For understanding the used commands and how they work, open a command prompt window, execute there the following commands, and read entirely all help pages displayed for each command very carefully.

• call /?
• echo /?
• for /?
• goto /?
• if /?
• pause /?
• reg /?
• reg query /?
• rem /?

Read also the Microsoft article about Using Command Redirection Operators for an explanation of 2>nul whereby redirection operator must be escaped in this batch code on FOR command line with caret character ^. And read answer on Single line with multiple commands using Windows batch file for an explanation of & operator.