Writing shell script to print a certain number of lines with certain arguments

Question

I have 5 variables and each variables contains five values.I want to print five lines with the five values from five variables one by one For example

$a=1 2 3 4          


        

Answer 1

Using this awk command with a bash loop:

for i in {1..5}; do
awk '{printf "My options was a=%d, b=%d, c=%d, d=%d and e=%d\n", $1, $2, $3, $4, $5}' <<< $(awk '{print $'$i'}' <(echo -e "$a\n$b\n$c\n$d\n$e") | tr $'\n' ' '); done

Output:

$ a='1 2 3 4 5'
$ b='4 2 3 4 5'
$ c='8 9 7 6 5'
$ d='8 7 6 5 4'
$ e='5 6 7 3 3'
$ for i in {1..5}; do
awk '{printf "My options was a=%d, b=%d, c=%d, d=%d and e=%d\n", $1, $2, $3, $4, $5}' <<< $(awk '{print $'$i'}' <(echo -e "$a\n$b\n$c\n$d\n$e") | tr $'\n' ' '); done
My options was a=1, b=4, c=8, d=8 and e=5
My options was a=2, b=2, c=9, d=7 and e=6
My options was a=3, b=3, c=7, d=6 and e=7
My options was a=4, b=4, c=6, d=5 and e=3
My options was a=5, b=5, c=5, d=4 and e=3