better writing style for the following code

Question

I was wondering if someone could tell me the pythonic way to check out the following.

I have a 6 bit binary number and want to check with its decimal values. Using mathe

Answer 1

Personally I prefer a if/elif if I am understanding your ...

so your:

if(a==1):
    ....
else:
    if(a==2)
.....

Becomes this if you use if elif ladder:

if a==1:
    ....
elif a==2:
    .....
else:
    default

You can also use Python's version of a conditional expression for simple ladders:

def one():
   print("option 1 it is\n")

def two():
   print("option 2 it is\n")

def three():
   print("not one or two\n")

one() if a==1 else two() if a==2 else three()

Or even dictionaries:

def one():
   print("option 1 it is\n")

def two():
   print("option 2 it is\n")

def three():
   print("not one or two\n")

options = {1:one,
           2:two,
           3:three,
}

options[2]()

There is a great discussion on Python forms of switch-case in this SO post.