mysqli_prepare() expects parameter 1 to be mysqli

Question

Having trouble with procedural use of mysqli

Here\'s the function:

db.php

Answer 1

The way the two files db.php and function.php are glued together I think results in $link being defined as a global variable - you need to use global to access it within function:

function addItemToCatalog($var1, $var2, $var3, $var4) {
    global $link;
    ...
}

or give the $link to the function explicitly through parameter:

function addItemToCatalog($var1, $var2, $var3, $var4, $link) {
    ...
}