How to get opened application in windows(taskmanager ->application tab content) using java code

Question

Below one is used for get list of processes from the windows

       Process proc = Runtime.getRuntime().exec (\"tasklist.exe\");

Answer 1

I am trying to give the answer, even if the post is already more than one year old.

Try with the following code snippet:

private static final String STR_MATCH = "My Java Application";
String strProcess;
BufferedReader input = null;

try { 
    if(System.getProperty("os.name").startsWith("Windows")) {
        Process p = Runtime.getRuntime().exec(System.getenv("windir") + "\\system32\\" + "tasklist.exe /v /FI \"STATUS eq RUNNING\" /FI \"imagename eq javaw.exe\"");
        input = new BufferedReader(new InputStreamReader(p.getInputStream()));

        while((strProcess = input.readLine()) != null) {
            if(strProcess.contains(STR_MATCH))
                /* lot of code here */
        }

        // Close resources
        input.close();
}
catch(IOEXception ioe) {
    /* handle exception */
}

The thing to notice here is the way used to get the Process p, i.e.:

Process p = Runtime.getRuntime().exec(System.getenv("windir") + "\\system32\\" + "tasklist.exe /v /FI \"STATUS eq RUNNING\" /FI \"imagename eq javaw.exe\"");

The filter /FI "STATUS eq RUNNING" /FI "imagename eq javaw.exe" that has been added when invoking tasklist.exe allows to get more information related to the process javaw.exe, including the Window/Application name.