If I have two arguments [[1 2] [3 4]] and [5 6], how can I get to [[1 5] [2 6] [3 5] [4 6]].
I thought I may have to use for so I tried,
for
(fo
(mapcat #(map vector % [5 6]) [[1 2] [3 4]])
or using for:
(for [c [[1 2] [3 4]] p (map vector c [5 6])] p)