Get current path of executed file

Question

I try to write and read to the file in my java project file called Books.txt. The problem is that I can access the file only if partialPath has full path to the file.

He

Answer 1

I also feel that files created (and later possibly modified and or deleted) by your running Java application is usually better to be placed in a location of the file system that is away from your java application installed home directory. An example might be the 'C:\ProgramData\ApplicationNameFiles\' for the Windows operating system or something similar for other OS platforms. In my opinion, at least for me, I feel it provides less chance of corruption to essential application files due to a poorly maintained drive or, accidental deletion by a User that opens up a File Explorer and decides to take it upon him/her self to clean their system of so called unnecessary files, and other not so obvious reasons.

Because Java can run on almost any platform and such data file locations are platform specific the User should be allowed to select the location to where these files can be created and manipulated from. This location then can be saved as a Property. Indeed, slightly more work but IMHO I feel it may be well worth it.

It is obviously much easier to create a directory (folder) within the install home directory of your JAR file when it's first started and then store and manipulate your application's created data files from there. Definitely much easier to find but then again...that would be a matter of opinion and it wouldn't be mine. Never-the-less if you're bent on doing it this way then your Java application's Install Utility should definitely know where that install path would be, it is therefore just a matter of storing that location somewhere.

No Install Utility? Well then your Java application will definitely need a means to know from where your JAR file is running from and the following code is one way to do that:

public String applicationPath(Class mainStartupClassName) {
    try {
        String path = mainStartupClassName.getProtectionDomain().getCodeSource().getLocation().getPath();
        String pathDecoded = URLDecoder.decode(path, "UTF-8");
        pathDecoded = pathDecoded.trim().replace("/", File.separator);
        if (pathDecoded.startsWith(File.separator)) {
            pathDecoded = pathDecoded.substring(1);
        }
        return pathDecoded;
    }
    catch (UnsupportedEncodingException ex) {
        Logger.getLogger("applicationPath() Method").log(Level.SEVERE, null, ex);
    }
    return null;
}

And here is how you would use this method:

String appPath = applicationPath(MyMainStartupClassName.class);

Do keep in mind that if this method is run from within your IDE it will most likely not return the path to your JAR file but instead point to a folder where your classes are stored for the application build.