In C++ float value being truncated from double

Question

I\'ve coded using float variables before and never had this problem.

float  a, b, subtotal, stx;
a=15.95;
b=24.95;
subtotal=a+b;
stx=subtotal*.07;

cout <         


        

Answer 1

why is the compiler interpreting the literal values as as doubles

Because that's how literals are interpreted, unless you add modifiers to specify a different type.

a=15.95f;
       ^ gives the literal "float" type

But if variables are declared as float...

The type of an expression never depends on how the expression is used; so 15.95 has type double whatever you do with it. The type is converted for use in a larger expression, if necessary, and that's what gives the warning in this case.