type casting of byte and int

Question

I\'d a code snippet:

class AutoTypeCast{
    public static void main(String...args){
        int x=10;
        byte b=20;//no compilation error
        byte c=x;         


        

Answer 1

Because compiler is not able to figure out the value of X at compile time. So it assume that X can contain value which is greater than byte range. If you make variable X as final then it will not give you compile time error.

        final int x=10;
        byte b=20;//no compilation error
        byte c=x;//no compilation error