Why does (x-1) toggle all the bits from the rightmost set bit of x?

Question

Why does this property hold true?

say the kth bit from right side is the first set bit in number \'x\'. (x-1) will toggle every bit upto kth bit from r

Answer 1

It's the same reason if you do (x-1) where x is a base 10 integers all the zeros (if any) on the right will become nines.

9324930000000 - 1 = 9324929999999