Sort alphanumeric array, consecutive numbers should reside at last

Question

I want to sort an alphanumeric, but numbers should come at end instead of beginning. for instance

let array = [\"1\", \"a\", \"b\", \"z\", \"3\", \"!\"]
let sor         


        

Answer 1

Assume that you want to receive "numbers should come at end instead of beginning", without watching your example with unexpected "!" sorting. Then you can do this:

let array = ["1", "a", "b", "z", "3", "!"]
let sortedArray = array.sort { (firstObject, secondObject) -> Bool in
    let firstIsNumber = firstObject.rangeOfCharacterFromSet(NSCharacterSet.decimalDigitCharacterSet())?.count > 0
    let secondIsNumber = secondObject.rangeOfCharacterFromSet(NSCharacterSet.decimalDigitCharacterSet())?.count > 0
    if firstIsNumber != secondIsNumber {return secondIsNumber}
    return firstObject < secondObject
}
print(sortedArray)
//["!", "a", "b", "z", "1", "3"]