Display a number decimal format instead as an exponential in cout

Question

I calculated a total of floats and I got a number like 509990e-405. I\'m assuming this is the short version; how can I cout this as a full number?

Answer 1

You can force the output to be not in scientific notation, and to have the sufficient precision to show your small number.

#include 

// ...

long double d = 509990e-405L;
std::cout << std::fixed << std::setprecision(410) << d << std::endl;

Output:

0.00000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000050999000000

If you really want this is another question.